Base | Representation |
---|---|
bin | 10010111010001101… |
… | …101101001101110001 |
3 | 1221102000121022100221 |
4 | 102322031231031301 |
5 | 313040312240213 |
6 | 13154425413041 |
7 | 1316103234340 |
oct | 227215551561 |
9 | 57360538327 |
10 | 20304024433 |
11 | 867a102090 |
12 | 3b2793a181 |
13 | 1bb7684454 |
14 | da8825b57 |
15 | 7dc7c238d |
hex | 4ba36d371 |
20304024433 has 32 divisors (see below), whose sum is σ = 26776737792. Its totient is φ = 14926032000.
The previous prime is 20304024431. The next prime is 20304024493. The reversal of 20304024433 is 33442040302.
It is not a de Polignac number, because 20304024433 - 21 = 20304024431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20304024398 and 20304024407.
It is not an unprimeable number, because it can be changed into a prime (20304024431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 50758 + ... + 207808.
It is an arithmetic number, because the mean of its divisors is an integer number (836773056).
Almost surely, 220304024433 is an apocalyptic number.
20304024433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
20304024433 is a deficient number, since it is larger than the sum of its proper divisors (6472713359).
20304024433 is a wasteful number, since it uses less digits than its factorization.
20304024433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157165.
The product of its (nonzero) digits is 6912, while the sum is 25.
Adding to 20304024433 its reverse (33442040302), we get a palindrome (53746064735).
The spelling of 20304024433 in words is "twenty billion, three hundred four million, twenty-four thousand, four hundred thirty-three".
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