Base | Representation |
---|---|
bin | 101110011001001111001011… |
… | …111101100001100001011011 |
3 | 222202110110100101021220210022 |
4 | 232121033023331201201123 |
5 | 203221030444401442021 |
6 | 2001544415113541055 |
7 | 60656503161505136 |
oct | 5631171375414133 |
9 | 882413311256708 |
10 | 204044433234011 |
11 | 5a018838151317 |
12 | 1aa75217a1478b |
13 | 89b13cc737b56 |
14 | 3855b3621b21d |
15 | 188c9e5d321ab |
hex | b993cbf6185b |
204044433234011 has 4 divisors (see below), whose sum is σ = 204079607250024. Its totient is φ = 204009259218000.
The previous prime is 204044433233983. The next prime is 204044433234023. The reversal of 204044433234011 is 110432334440402.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 204044433234011 - 26 = 204044433233947 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (204044433284011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17586999305 + ... + 17587010906.
It is an arithmetic number, because the mean of its divisors is an integer number (51019901812506).
Almost surely, 2204044433234011 is an apocalyptic number.
204044433234011 is a deficient number, since it is larger than the sum of its proper divisors (35174016013).
204044433234011 is an equidigital number, since it uses as much as digits as its factorization.
204044433234011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35174016012.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 204044433234011 its reverse (110432334440402), we get a palindrome (314476767674413).
The spelling of 204044433234011 in words is "two hundred four trillion, forty-four billion, four hundred thirty-three million, two hundred thirty-four thousand, eleven".
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