211001100113 has 2 divisors, whose sum is σ = 211001100114. Its totient is φ = 211001100112.

The previous prime is 211001100097. The next prime is 211001100127. The reversal of 211001100113 is 311001100112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 197023240129 + 13977859984 = 443873^2 + 118228^2 .

It is a cyclic number.

It is not a de Polignac number, because 211001100113 - 2⁴ = 211001100097 is a prime.

It is a super-2 number, since 2×211001100113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211001100094 and 211001100103.

It is not a weakly prime, because it can be changed into another prime (211001100173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105500550056 + 105500550057.

It is an arithmetic number, because the mean of its divisors is an integer number (105500550057).

Almost surely, 2^211001100113 is an apocalyptic number.

It is an amenable number.

211001100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211001100113 is an equidigital number, since it uses as much as digits as its factorization.

211001100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 211001100113 its reverse (311001100112), we get a palindrome (522002200225).

Subtracting 211001100113 from its reverse (311001100112), we obtain a palindrome (99999999999).

The spelling of 211001100113 in words is "two hundred eleven billion, one million, one hundred thousand, one hundred thirteen".