211130000 has 100 divisors (see below), whose sum is σ = 524119728. Its totient is φ = 82320000.

The previous prime is 211129999. The next prime is 211130009. The reversal of 211130000 is 31112.

It is a tau number, because it is divible by the number of its divisors (100).

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a self number, because there is not a number n which added to its sum of digits gives 211130000.

It is not an unprimeable number, because it can be changed into a prime (211130009) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 429755 + ... + 430245.

Almost surely, 2^211130000 is an apocalyptic number.

211130000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (262059864).

211130000 is an abundant number, since it is smaller than the sum of its proper divisors (312989728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211130000 is an equidigital number, since it uses as much as digits as its factorization.

211130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 562 (or 541 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 8.

The square root of 211130000 is about 14530.3131418425. The cubic root of 211130000 is about 595.4564207367.

Adding to 211130000 its reverse (31112), we get a palindrome (211161112).

The spelling of 211130000 in words is "two hundred eleven million, one hundred thirty thousand".