Base | Representation |
---|---|
bin | 1100010010100001010… |
… | …1001001101110011101 |
3 | 202011222000101211201222 |
4 | 3010220111021232131 |
5 | 11424343241443010 |
6 | 240554121143125 |
7 | 21152666436665 |
oct | 3045025115635 |
9 | 664860354658 |
10 | 211130031005 |
11 | 815a3442233 |
12 | 34b0302aaa5 |
13 | 16ba917343a |
14 | a30c35d1a5 |
15 | 575a64b355 |
hex | 3128549b9d |
211130031005 has 8 divisors (see below), whose sum is σ = 266690565600. Its totient is φ = 160014339216.
The previous prime is 211130030999. The next prime is 211130031083. The reversal of 211130031005 is 500130031112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 211130031005 - 212 = 211130026909 is a prime.
It is a super-2 number, since 2×2111300310052 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1111210595 + ... + 1111210784.
It is an arithmetic number, because the mean of its divisors is an integer number (33336320700).
Almost surely, 2211130031005 is an apocalyptic number.
It is an amenable number.
211130031005 is a deficient number, since it is larger than the sum of its proper divisors (55560534595).
211130031005 is a wasteful number, since it uses less digits than its factorization.
211130031005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2222421403.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 211130031005 its reverse (500130031112), we get a palindrome (711260062117).
The spelling of 211130031005 in words is "two hundred eleven billion, one hundred thirty million, thirty-one thousand, five".
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