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211130031005 = 5192222421379
BaseRepresentation
bin1100010010100001010…
…1001001101110011101
3202011222000101211201222
43010220111021232131
511424343241443010
6240554121143125
721152666436665
oct3045025115635
9664860354658
10211130031005
11815a3442233
1234b0302aaa5
1316ba917343a
14a30c35d1a5
15575a64b355
hex3128549b9d

211130031005 has 8 divisors (see below), whose sum is σ = 266690565600. Its totient is φ = 160014339216.

The previous prime is 211130030999. The next prime is 211130031083. The reversal of 211130031005 is 500130031112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 211130031005 - 212 = 211130026909 is a prime.

It is a super-2 number, since 2×2111300310052 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1111210595 + ... + 1111210784.

It is an arithmetic number, because the mean of its divisors is an integer number (33336320700).

Almost surely, 2211130031005 is an apocalyptic number.

It is an amenable number.

211130031005 is a deficient number, since it is larger than the sum of its proper divisors (55560534595).

211130031005 is a wasteful number, since it uses less digits than its factorization.

211130031005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2222421403.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 211130031005 its reverse (500130031112), we get a palindrome (711260062117).

The spelling of 211130031005 in words is "two hundred eleven billion, one hundred thirty million, thirty-one thousand, five".

Divisors: 1 5 19 95 2222421379 11112106895 42226006201 211130031005