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211141200000 = 27355251701
BaseRepresentation
bin1100010010100011111…
…1110000100010000000
3202011222210102021201110
43010220333300202000
511424404121400000
6240555200403320
721153163405443
oct3045077604200
9664883367643
10211141200000
11815a9780705
1234b06916540
1316bab584103
14a30da2965a
15575b605850
hex3128ff0880

211141200000 has 384 divisors, whose sum is σ = 704806764480. Its totient is φ = 56000000000.

The previous prime is 211141199993. The next prime is 211141200037. The reversal of 211141200000 is 2141112.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 301199650 + ... + 301200350.

Almost surely, 2211141200000 is an apocalyptic number.

211141200000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211141200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (352403382240).

211141200000 is an abundant number, since it is smaller than the sum of its proper divisors (493665564480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211141200000 is an frugal number, since it uses more digits than its factorization.

211141200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 994 (or 962 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 12.

Adding to 211141200000 its reverse (2141112), we get a palindrome (211143341112).

The spelling of 211141200000 in words is "two hundred eleven billion, one hundred forty-one million, two hundred thousand".