Base | Representation |
---|---|
bin | 11110101110011111011… |
… | …110011101011001011101 |
3 | 21110212011101020120101211 |
4 | 132232133132131121131 |
5 | 234043330123120123 |
6 | 4254002313304421 |
7 | 305360023103533 |
oct | 36563736353135 |
9 | 7425141216354 |
10 | 2111504504413 |
11 | 744536278377 |
12 | 2a1282705111 |
13 | 12416366c875 |
14 | 742a97ca153 |
15 | 39dd220e40d |
hex | 1eb9f79d65d |
2111504504413 has 2 divisors, whose sum is σ = 2111504504414. Its totient is φ = 2111504504412.
The previous prime is 2111504504407. The next prime is 2111504504441. The reversal of 2111504504413 is 3144054051112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1985920737529 + 125583766884 = 1409227^2 + 354378^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111504504413 - 213 = 2111504496221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111504501413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055752252206 + 1055752252207.
It is an arithmetic number, because the mean of its divisors is an integer number (1055752252207).
Almost surely, 22111504504413 is an apocalyptic number.
It is an amenable number.
2111504504413 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111504504413 is an equidigital number, since it uses as much as digits as its factorization.
2111504504413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 2111504504413 its reverse (3144054051112), we get a palindrome (5255558555525).
The spelling of 2111504504413 in words is "two trillion, one hundred eleven billion, five hundred four million, five hundred four thousand, four hundred thirteen".
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