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2112113 = 23131701
BaseRepresentation
bin1000000011101001110001
310222022021102
420003221301
51020041423
6113134145
723644523
oct10035161
93868242
102112113
111212953
1285a355
1358c493
143cda13
152bac28
hex203a71

2112113 has 8 divisors (see below), whose sum is σ = 2223936. Its totient is φ = 2002000.

The previous prime is 2112107. The next prime is 2112127. The reversal of 2112113 is 3112112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2112113 - 210 = 2111089 is a prime.

It is a super-2 number, since 2×21121132 = 8922042649538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112094 and 2112103.

It is not an unprimeable number, because it can be changed into a prime (2112193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2663 + ... + 3363.

It is an arithmetic number, because the mean of its divisors is an integer number (277992).

22112113 is an apocalyptic number.

2112113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

2112113 is a deficient number, since it is larger than the sum of its proper divisors (111823).

2112113 is a wasteful number, since it uses less digits than its factorization.

2112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 855.

The product of its digits is 12, while the sum is 11.

The square root of 2112113 is about 1453.3110472297. The cubic root of 2112113 is about 128.3036613622.

Adding to 2112113 its reverse (3112112), we get a palindrome (5224225).

Subtracting 2112113 from its reverse (3112112), we obtain a palindrome (999999).

The spelling of 2112113 in words is "two million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 23 131 701 3013 16123 91831 2112113