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211220011021181 is a prime number
BaseRepresentation
bin110000000001101001111101…
…101110011111001101111101
31000200212102202201211121211212
4300001221331232133031331
5210141112040310134211
62025121044500454205
762330066530363601
oct6001517556371575
91020772681747755
10211220011021181
11613349a37aa898
121b833a2a3aa365
1390b1c66768326
143a23162bd1501
1519644b58b438b
hexc01a7db9f37d

211220011021181 has 2 divisors, whose sum is σ = 211220011021182. Its totient is φ = 211220011021180.

The previous prime is 211220011021027. The next prime is 211220011021223. The reversal of 211220011021181 is 181120110022112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118741688621956 + 92478322399225 = 10896866^2 + 9616565^2 .

It is a cyclic number.

It is not a de Polignac number, because 211220011021181 - 210 = 211220011020157 is a prime.

It is a super-2 number, since 2×2112200110211812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211220011020181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610005510590 + 105610005510591.

It is an arithmetic number, because the mean of its divisors is an integer number (105610005510591).

Almost surely, 2211220011021181 is an apocalyptic number.

It is an amenable number.

211220011021181 is a deficient number, since it is larger than the sum of its proper divisors (1).

211220011021181 is an equidigital number, since it uses as much as digits as its factorization.

211220011021181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 23.

Adding to 211220011021181 its reverse (181120110022112), we get a palindrome (392340121043293).

The spelling of 211220011021181 in words is "two hundred eleven trillion, two hundred twenty billion, eleven million, twenty-one thousand, one hundred eighty-one".