Base | Representation |
---|---|
bin | 10011101011101100… |
… | …010111101100011101 |
3 | 2000112212121212112111 |
4 | 103223230113230131 |
5 | 321240320140313 |
6 | 13413042034021 |
7 | 1345503164656 |
oct | 235354275435 |
9 | 60485555474 |
10 | 21134146333 |
11 | 8a65746a43 |
12 | 4119948911 |
13 | 1cba652941 |
14 | 1046b9252d |
15 | 83a5e943d |
hex | 4ebb17b1d |
21134146333 has 2 divisors, whose sum is σ = 21134146334. Its totient is φ = 21134146332.
The previous prime is 21134146277. The next prime is 21134146339. The reversal of 21134146333 is 33364143112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18901300324 + 2232846009 = 137482^2 + 47253^2 .
It is a cyclic number.
It is not a de Polignac number, because 21134146333 - 225 = 21100591901 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21134146295 and 21134146304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21134146339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10567073166 + 10567073167.
It is an arithmetic number, because the mean of its divisors is an integer number (10567073167).
Almost surely, 221134146333 is an apocalyptic number.
It is an amenable number.
21134146333 is a deficient number, since it is larger than the sum of its proper divisors (1).
21134146333 is an equidigital number, since it uses as much as digits as its factorization.
21134146333 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15552, while the sum is 31.
Adding to 21134146333 its reverse (33364143112), we get a palindrome (54498289445).
The spelling of 21134146333 in words is "twenty-one billion, one hundred thirty-four million, one hundred forty-six thousand, three hundred thirty-three".
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