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BaseRepresentation
bin1100010101110011110…
…1110111111011100101
3202021020120002110211012
43011130331313323211
511433200324340003
6241221504552005
721213611540063
oct3053475677345
9667216073735
10212013121253
1181a06974a8a
123510a922605
1316cba0c914b
14a393757033
1557ace378d8
hex315cf77ee5

212013121253 has 2 divisors, whose sum is σ = 212013121254. Its totient is φ = 212013121252.

The previous prime is 212013121237. The next prime is 212013121261. The reversal of 212013121253 is 352121310212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 137820622564 + 74192498689 = 371242^2 + 272383^2 .

It is a cyclic number.

It is not a de Polignac number, because 212013121253 - 24 = 212013121237 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212013121753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006560626 + 106006560627.

It is an arithmetic number, because the mean of its divisors is an integer number (106006560627).

Almost surely, 2212013121253 is an apocalyptic number.

It is an amenable number.

212013121253 is a deficient number, since it is larger than the sum of its proper divisors (1).

212013121253 is an equidigital number, since it uses as much as digits as its factorization.

212013121253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 212013121253 its reverse (352121310212), we get a palindrome (564134431465).

The spelling of 212013121253 in words is "two hundred twelve billion, thirteen million, one hundred twenty-one thousand, two hundred fifty-three".