Base | Representation |
---|---|
bin | 1100010101110011110… |
… | …1110111111011100101 |
3 | 202021020120002110211012 |
4 | 3011130331313323211 |
5 | 11433200324340003 |
6 | 241221504552005 |
7 | 21213611540063 |
oct | 3053475677345 |
9 | 667216073735 |
10 | 212013121253 |
11 | 81a06974a8a |
12 | 3510a922605 |
13 | 16cba0c914b |
14 | a393757033 |
15 | 57ace378d8 |
hex | 315cf77ee5 |
212013121253 has 2 divisors, whose sum is σ = 212013121254. Its totient is φ = 212013121252.
The previous prime is 212013121237. The next prime is 212013121261. The reversal of 212013121253 is 352121310212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 137820622564 + 74192498689 = 371242^2 + 272383^2 .
It is a cyclic number.
It is not a de Polignac number, because 212013121253 - 24 = 212013121237 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212013121753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006560626 + 106006560627.
It is an arithmetic number, because the mean of its divisors is an integer number (106006560627).
Almost surely, 2212013121253 is an apocalyptic number.
It is an amenable number.
212013121253 is a deficient number, since it is larger than the sum of its proper divisors (1).
212013121253 is an equidigital number, since it uses as much as digits as its factorization.
212013121253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 212013121253 its reverse (352121310212), we get a palindrome (564134431465).
The spelling of 212013121253 in words is "two hundred twelve billion, thirteen million, one hundred twenty-one thousand, two hundred fifty-three".
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