Base | Representation |
---|---|
bin | 110000001110110011000010… |
… | …101111010001001001001011 |
3 | 1000211001202211101122000202101 |
4 | 300032303002233101021023 |
5 | 210300411113132020424 |
6 | 2031052002400414231 |
7 | 62452250314050253 |
oct | 6016630257211113 |
9 | 1024052741560671 |
10 | 212123111985739 |
11 | 616529a7750209 |
12 | 1b95aa69017377 |
13 | 914917b7c94b6 |
14 | 3a54b55d82963 |
15 | 197cc2027a344 |
hex | c0ecc2bd124b |
212123111985739 has 2 divisors, whose sum is σ = 212123111985740. Its totient is φ = 212123111985738.
The previous prime is 212123111985689. The next prime is 212123111985791. The reversal of 212123111985739 is 937589111321212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212123111985739 - 213 = 212123111977547 is a prime.
It is a super-2 number, since 2×2121231119857392 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 212123111985739.
It is not a weakly prime, because it can be changed into another prime (212123111985139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106061555992869 + 106061555992870.
It is an arithmetic number, because the mean of its divisors is an integer number (106061555992870).
Almost surely, 2212123111985739 is an apocalyptic number.
212123111985739 is a deficient number, since it is larger than the sum of its proper divisors (1).
212123111985739 is an equidigital number, since it uses as much as digits as its factorization.
212123111985739 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1632960, while the sum is 55.
The spelling of 212123111985739 in words is "two hundred twelve trillion, one hundred twenty-three billion, one hundred eleven million, nine hundred eighty-five thousand, seven hundred thirty-nine".
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