Base | Representation |
---|---|
bin | 1001101001011001010011… |
… | …01101101011011000111001 |
3 | 2210002222212022022022011111 |
4 | 10310230221231223120321 |
5 | 10240030314042040001 |
6 | 113041211155000321 |
7 | 4316425244012212 |
oct | 464545155533071 |
9 | 83088768268144 |
10 | 21213543315001 |
11 | 6839682190144 |
12 | 24673b08990a1 |
13 | bab5756acbab |
14 | 534a53340409 |
15 | 26bc2da45851 |
hex | 134b29b6b639 |
21213543315001 has 8 divisors (see below), whose sum is σ = 21907205297408. Its totient is φ = 20520465966000.
The previous prime is 21213543314923. The next prime is 21213543315053. The reversal of 21213543315001 is 10051334531212.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21213543315001 - 29 = 21213543314489 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21213543315301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 146084595 + ... + 146229736.
It is an arithmetic number, because the mean of its divisors is an integer number (2738400662176).
Almost surely, 221213543315001 is an apocalyptic number.
It is an amenable number.
21213543315001 is a deficient number, since it is larger than the sum of its proper divisors (693661982407).
21213543315001 is a wasteful number, since it uses less digits than its factorization.
21213543315001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 292316703.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 21213543315001 its reverse (10051334531212), we get a palindrome (31264877846213).
The spelling of 21213543315001 in words is "twenty-one trillion, two hundred thirteen billion, five hundred forty-three million, three hundred fifteen thousand, one".
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