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BaseRepresentation
bin1001101001011001010011…
…01101101011011010000001
32210002222212022022022021011
410310230221231223122001
510240030314042040243
6113041211155000521
74316425244012344
oct464545155533201
983088768268234
1021213543315073
1168396821901aa
1224673b0899141
13bab5756acc35
14534a5334045b
1526bc2da4589d
hex134b29b6b681

21213543315073 has 2 divisors, whose sum is σ = 21213543315074. Its totient is φ = 21213543315072.

The previous prime is 21213543315053. The next prime is 21213543315143. The reversal of 21213543315073 is 37051334531212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17442458957889 + 3771084357184 = 4176417^2 + 1941928^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21213543315073 is a prime.

It is not a weakly prime, because it can be changed into another prime (21213543315053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606771657536 + 10606771657537.

It is an arithmetic number, because the mean of its divisors is an integer number (10606771657537).

Almost surely, 221213543315073 is an apocalyptic number.

It is an amenable number.

21213543315073 is a deficient number, since it is larger than the sum of its proper divisors (1).

21213543315073 is an equidigital number, since it uses as much as digits as its factorization.

21213543315073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 40.

Adding to 21213543315073 its reverse (37051334531212), we get a palindrome (58264877846285).

The spelling of 21213543315073 in words is "twenty-one trillion, two hundred thirteen billion, five hundred forty-three million, three hundred fifteen thousand, seventy-three".