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21213543315143 is a prime number
BaseRepresentation
bin1001101001011001010011…
…01101101011011011000111
32210002222212022022022100202
410310230221231223123013
510240030314042041033
6113041211155001115
74316425244012504
oct464545155533307
983088768268322
1021213543315143
116839682190263
1224673b089919b
13bab5756acc8a
14534a533404ab
1526bc2da458e8
hex134b29b6b6c7

21213543315143 has 2 divisors, whose sum is σ = 21213543315144. Its totient is φ = 21213543315142.

The previous prime is 21213543315073. The next prime is 21213543315233. The reversal of 21213543315143 is 34151334531212.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21213543315143 - 236 = 21144823838407 is a prime.

It is a super-2 number, since 2×212135433151432 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21213543315097 and 21213543315106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21213542315143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606771657571 + 10606771657572.

It is an arithmetic number, because the mean of its divisors is an integer number (10606771657572).

Almost surely, 221213543315143 is an apocalyptic number.

21213543315143 is a deficient number, since it is larger than the sum of its proper divisors (1).

21213543315143 is an equidigital number, since it uses as much as digits as its factorization.

21213543315143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 38.

Adding to 21213543315143 its reverse (34151334531212), we get a palindrome (55364877846355).

The spelling of 21213543315143 in words is "twenty-one trillion, two hundred thirteen billion, five hundred forty-three million, three hundred fifteen thousand, one hundred forty-three".