Base | Representation |
---|---|
bin | 11110111000010111101… |
… | …011011010010011101111 |
3 | 21111212112120102110102201 |
4 | 132320113223122103233 |
5 | 234232040420201033 |
6 | 4302515005402331 |
7 | 306213614505256 |
oct | 36702753322357 |
9 | 7455476373381 |
10 | 2122111100143 |
11 | 748a89435771 |
12 | 2a33428693a7 |
13 | 125163c24b08 |
14 | 749d433179d |
15 | 3a30348e47d |
hex | 1ee17ada4ef |
2122111100143 has 2 divisors, whose sum is σ = 2122111100144. Its totient is φ = 2122111100142.
The previous prime is 2122111100111. The next prime is 2122111100167. The reversal of 2122111100143 is 3410011112212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2122111100143 - 25 = 2122111100111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2122111100143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2122111170143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061055550071 + 1061055550072.
It is an arithmetic number, because the mean of its divisors is an integer number (1061055550072).
Almost surely, 22122111100143 is an apocalyptic number.
2122111100143 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122111100143 is an equidigital number, since it uses as much as digits as its factorization.
2122111100143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 2122111100143 its reverse (3410011112212), we get a palindrome (5532122212355).
The spelling of 2122111100143 in words is "two trillion, one hundred twenty-two billion, one hundred eleven million, one hundred thousand, one hundred forty-three".
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