Base | Representation |
---|---|
bin | 111111100000110… |
… | …0011000010100100 |
3 | 12111112001201012210 |
4 | 1333001203002210 |
5 | 13331031041400 |
6 | 551245043420 |
7 | 103545103545 |
oct | 17701430244 |
9 | 5445051183 |
10 | 2131112100 |
11 | 9a3a59077 |
12 | 4b5856570 |
13 | 27c6920a0 |
14 | 1630684cc |
15 | c7160950 |
hex | 7f0630a4 |
2131112100 has 144 divisors (see below), whose sum is σ = 6679225280. Its totient is φ = 521510400.
The previous prime is 2131112099. The next prime is 2131112101. The reversal of 2131112100 is 12111312.
It is an interprime number because it is at equal distance from previous prime (2131112099) and next prime (2131112101).
It is a Harshad number since it is a multiple of its sum of digits (12).
It is not an unprimeable number, because it can be changed into a prime (2131112101) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 704391 + ... + 707409.
Almost surely, 22131112100 is an apocalyptic number.
2131112100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2131112100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3339612640).
2131112100 is an abundant number, since it is smaller than the sum of its proper divisors (4548113180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2131112100 is a wasteful number, since it uses less digits than its factorization.
2131112100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3230 (or 3223 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 12.
The square root of 2131112100 is about 46163.9697166524. The cubic root of 2131112100 is about 1286.8722374016.
Adding to 2131112100 its reverse (12111312), we get a palindrome (2143223412).
It can be divided in two parts, 21311 and 12100, that added together give a triangular number (33411 = T258).
The spelling of 2131112100 in words is "two billion, one hundred thirty-one million, one hundred twelve thousand, one hundred".
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