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213112111301 = 516834123447
BaseRepresentation
bin1100011001111001111…
…0001100000011000101
3202101002011000221202022
43012132132030003011
511442423200030201
6241522524052525
721253055025515
oct3063636140305
9671064027668
10213112111301
118242025a521
1235376994145
13171339b520b
14a4596b1845
15582466e41b
hex319e78c0c5

213112111301 has 4 divisors (see below), whose sum is σ = 213116286432. Its totient is φ = 213107936172.

The previous prime is 213112111291. The next prime is 213112111307. The reversal of 213112111301 is 103111211312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213112111301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 213112111301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213112111307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2010041 + ... + 2113406.

It is an arithmetic number, because the mean of its divisors is an integer number (53279071608).

Almost surely, 2213112111301 is an apocalyptic number.

It is an amenable number.

213112111301 is a deficient number, since it is larger than the sum of its proper divisors (4175131).

213112111301 is an equidigital number, since it uses as much as digits as its factorization.

213112111301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4175130.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 213112111301 its reverse (103111211312), we get a palindrome (316223322613).

The spelling of 213112111301 in words is "two hundred thirteen billion, one hundred twelve million, one hundred eleven thousand, three hundred one".

Divisors: 1 51683 4123447 213112111301