Base | Representation |
---|---|
bin | 1001101100110010011011… |
… | …10100100000010001001111 |
3 | 2210112010202021010002011012 |
4 | 10312121031310200101033 |
5 | 10243433032434414411 |
6 | 113210530240115435 |
7 | 4331023042466012 |
oct | 466311564402117 |
9 | 83463667102135 |
10 | 21330113201231 |
11 | 6884060910a9a |
12 | 2485b03905b7b |
13 | bb9562059733 |
14 | 53a550cbb379 |
15 | 26eca27e618b |
hex | 13664dd2044f |
21330113201231 has 2 divisors, whose sum is σ = 21330113201232. Its totient is φ = 21330113201230.
The previous prime is 21330113201227. The next prime is 21330113201261. The reversal of 21330113201231 is 13210231103312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21330113201231 - 22 = 21330113201227 is a prime.
It is a super-2 number, since 2×213301132012312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21330113201197 and 21330113201206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21330113201261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10665056600615 + 10665056600616.
It is an arithmetic number, because the mean of its divisors is an integer number (10665056600616).
Almost surely, 221330113201231 is an apocalyptic number.
21330113201231 is a deficient number, since it is larger than the sum of its proper divisors (1).
21330113201231 is an equidigital number, since it uses as much as digits as its factorization.
21330113201231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 21330113201231 its reverse (13210231103312), we get a palindrome (34540344304543).
The spelling of 21330113201231 in words is "twenty-one trillion, three hundred thirty billion, one hundred thirteen million, two hundred one thousand, two hundred thirty-one".
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