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21344012341 = 84312531611
BaseRepresentation
bin10011111000001100…
…111100100000110101
32001002111112011120121
4103320030330200311
5322203031343331
613445540131541
71353632053141
oct237014744065
961074464517
1021344012341
119063158423
124178096bb1
132021c82802
1410669c2221
1584dc51c11
hex4f833c835

21344012341 has 4 divisors (see below), whose sum is σ = 21346552384. Its totient is φ = 21341472300.

The previous prime is 21344012321. The next prime is 21344012353. The reversal of 21344012341 is 14321044312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21344012341 - 231 = 19196528693 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21344012321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1257375 + ... + 1274236.

It is an arithmetic number, because the mean of its divisors is an integer number (5336638096).

Almost surely, 221344012341 is an apocalyptic number.

It is an amenable number.

21344012341 is a deficient number, since it is larger than the sum of its proper divisors (2540043).

21344012341 is an equidigital number, since it uses as much as digits as its factorization.

21344012341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2540042.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 21344012341 its reverse (14321044312), we get a palindrome (35665056653).

The spelling of 21344012341 in words is "twenty-one billion, three hundred forty-four million, twelve thousand, three hundred forty-one".

Divisors: 1 8431 2531611 21344012341