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2140442113 = 4315638821
BaseRepresentation
bin111111110010100…
…1000111000000001
312112011121201120211
41333211020320001
513340423121423
6552221034121
7104020313005
oct17745107001
95464551524
102140442113
119a9250927
124b89b5941
132815aa9c4
141643b6705
15c7da510d
hex7f948e01

2140442113 has 8 divisors (see below), whose sum is σ = 2149462656. Its totient is φ = 2131441200.

The previous prime is 2140442081. The next prime is 2140442141. The reversal of 2140442113 is 3112440412.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2140442113 - 25 = 2140442081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2140442713) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 238243 + ... + 247063.

It is an arithmetic number, because the mean of its divisors is an integer number (268682832).

Almost surely, 22140442113 is an apocalyptic number.

It is an amenable number.

2140442113 is a deficient number, since it is larger than the sum of its proper divisors (9020543).

2140442113 is an equidigital number, since it uses as much as digits as its factorization.

2140442113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9815.

The product of its (nonzero) digits is 768, while the sum is 22.

The square root of 2140442113 is about 46264.9123310528. The cubic root of 2140442113 is about 1288.7474798556.

Adding to 2140442113 its reverse (3112440412), we get a palindrome (5252882525).

The spelling of 2140442113 in words is "two billion, one hundred forty million, four hundred forty-two thousand, one hundred thirteen".