Base | Representation |
---|---|
bin | 1001101111111111001000… |
… | …11000101001010101010111 |
3 | 2210220122102101210200022120 |
4 | 10313333210120221111113 |
5 | 10302233121420042333 |
6 | 113333223423431023 |
7 | 4341663343221261 |
oct | 467774430512527 |
9 | 83818371720276 |
10 | 21440013440343 |
11 | 6916727713293 |
12 | 24a3275155473 |
13 | bc6a27997914 |
14 | 5419b8b32b31 |
15 | 272a85c84db3 |
hex | 137fe4629557 |
21440013440343 has 4 divisors (see below), whose sum is σ = 28586684587128. Its totient is φ = 14293342293560.
The previous prime is 21440013440341. The next prime is 21440013440369. The reversal of 21440013440343 is 34304431004412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21440013440343 - 21 = 21440013440341 is a prime.
It is a super-3 number, since 3×214400134403433 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21440013440341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3573335573388 + ... + 3573335573393.
It is an arithmetic number, because the mean of its divisors is an integer number (7146671146782).
Almost surely, 221440013440343 is an apocalyptic number.
21440013440343 is a deficient number, since it is larger than the sum of its proper divisors (7146671146785).
21440013440343 is an equidigital number, since it uses as much as digits as its factorization.
21440013440343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7146671146784.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 21440013440343 its reverse (34304431004412), we get a palindrome (55744444444755).
The spelling of 21440013440343 in words is "twenty-one trillion, four hundred forty billion, thirteen million, four hundred forty thousand, three hundred forty-three".
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