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221010113 is a prime number
BaseRepresentation
bin11010010110001…
…01100011000001
3120101212110212202
431023011203001
5423034310423
633533002545
75322361232
oct1513054301
9511773782
10221010113
11103833195
1262023455
1336a3241c
14214d1089
1514609728
hexd2c58c1

221010113 has 2 divisors, whose sum is σ = 221010114. Its totient is φ = 221010112.

The previous prime is 221010107. The next prime is 221010133. The reversal of 221010113 is 311010122.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 218359729 + 2650384 = 14777^2 + 1628^2 .

It is a cyclic number.

It is not a de Polignac number, because 221010113 - 28 = 221009857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 221010094 and 221010103.

It is not a weakly prime, because it can be changed into another prime (221010133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110505056 + 110505057.

It is an arithmetic number, because the mean of its divisors is an integer number (110505057).

Almost surely, 2221010113 is an apocalyptic number.

It is an amenable number.

221010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

221010113 is an equidigital number, since it uses as much as digits as its factorization.

221010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 221010113 is about 14866.4088804257. The cubic root of 221010113 is about 604.6035815764.

Adding to 221010113 its reverse (311010122), we get a palindrome (532020235).

Subtracting 221010113 from its reverse (311010122), we obtain a palindrome (90000009).

The spelling of 221010113 in words is "two hundred twenty-one million, ten thousand, one hundred thirteen".