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224332104013102 = 2112166052006551
BaseRepresentation
bin110011000000011101100011…
…010111110001010100101110
31002102021221101001002010122201
4303000131203113301110232
5213400424122111404402
62113040425035132114
765152313444024101
oct6300354327612456
91072257331063581
10224332104013102
116552a790431488
12211b10938a403a
1398235714266a7
143d57a35d80738
151ae05d5c74687
hexcc07635f152e

224332104013102 has 4 divisors (see below), whose sum is σ = 336498156019656. Its totient is φ = 112166052006550.

The previous prime is 224332104013097. The next prime is 224332104013111. The reversal of 224332104013102 is 201310401233422.

224332104013102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56083026003274 + ... + 56083026003277.

It is an arithmetic number, because the mean of its divisors is an integer number (84124539004914).

Almost surely, 2224332104013102 is an apocalyptic number.

224332104013102 is a deficient number, since it is larger than the sum of its proper divisors (112166052006554).

224332104013102 is a wasteful number, since it uses less digits than its factorization.

224332104013102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112166052006553.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 224332104013102 its reverse (201310401233422), we get a palindrome (425642505246524).

The spelling of 224332104013102 in words is "two hundred twenty-four trillion, three hundred thirty-two billion, one hundred four million, thirteen thousand, one hundred two".

Divisors: 1 2 112166052006551 224332104013102