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23104041 = 37701347
BaseRepresentation
bin101100000100…
…0101000101001
31121110210210020
41120020220221
521403312131
62143111053
7400244502
oct130105051
947423706
1023104041
1112050454
1278a2489
134a2c23c
1430d5ba9
152065996
hex1608a29

23104041 has 4 divisors (see below), whose sum is σ = 30805392. Its totient is φ = 15402692.

The previous prime is 23104027. The next prime is 23104049. The reversal of 23104041 is 14040132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23104041 - 25 = 23104009 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23104041.

It is not an unprimeable number, because it can be changed into a prime (23104049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3850671 + ... + 3850676.

It is an arithmetic number, because the mean of its divisors is an integer number (7701348).

Almost surely, 223104041 is an apocalyptic number.

It is an amenable number.

23104041 is a deficient number, since it is larger than the sum of its proper divisors (7701351).

23104041 is an equidigital number, since it uses as much as digits as its factorization.

23104041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7701350.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 23104041 is about 4806.6663083680. Note that the first 3 decimals coincide. The cubic root of 23104041 is about 284.8148628319.

Adding to 23104041 its reverse (14040132), we get a palindrome (37144173).

The spelling of 23104041 in words is "twenty-three million, one hundred four thousand, forty-one".

Divisors: 1 3 7701347 23104041