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2311144204049 is a prime number
BaseRepresentation
bin100001101000011010111…
…011011110011100010001
322011221110121120002201022
4201220122323132130101
5300331210404012144
64525420333045225
7325655210413262
oct41503273363421
98157417502638
102311144204049
1181117271957a
12313ab9626815
13139c2b13a355
147dc07abc969
15401b8c12cee
hex21a1aede711

2311144204049 has 2 divisors, whose sum is σ = 2311144204050. Its totient is φ = 2311144204048.

The previous prime is 2311144204001. The next prime is 2311144204063. The reversal of 2311144204049 is 9404024411132.

2311144204049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2063911503424 + 247232700625 = 1436632^2 + 497225^2 .

It is a cyclic number.

It is not a de Polignac number, because 2311144204049 - 212 = 2311144199953 is a prime.

It is not a weakly prime, because it can be changed into another prime (2311144204349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155572102024 + 1155572102025.

It is an arithmetic number, because the mean of its divisors is an integer number (1155572102025).

Almost surely, 22311144204049 is an apocalyptic number.

It is an amenable number.

2311144204049 is a deficient number, since it is larger than the sum of its proper divisors (1).

2311144204049 is an equidigital number, since it uses as much as digits as its factorization.

2311144204049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 2311144204049 in words is "two trillion, three hundred eleven billion, one hundred forty-four million, two hundred four thousand, forty-nine".