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23313312332953 is a prime number
BaseRepresentation
bin1010100110100000011011…
…01100110011110010011001
310001112201201211011101120121
411103100031230303302121
511023431130424123303
6121325553212153241
74624221420122566
oct523201554636231
9101481654141517
1023313312332953
117479136042875
122746339168821
13100158893c716
145a85282c586d
152a66758339bd
hex15340db33c99

23313312332953 has 2 divisors, whose sum is σ = 23313312332954. Its totient is φ = 23313312332952.

The previous prime is 23313312332929. The next prime is 23313312332971. The reversal of 23313312332953 is 35923321331332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15394221061209 + 7919091271744 = 3923547^2 + 2814088^2 .

It is a cyclic number.

It is not a de Polignac number, because 23313312332953 - 237 = 23175873379481 is a prime.

It is not a weakly prime, because it can be changed into another prime (23313312335953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11656656166476 + 11656656166477.

It is an arithmetic number, because the mean of its divisors is an integer number (11656656166477).

Almost surely, 223313312332953 is an apocalyptic number.

It is an amenable number.

23313312332953 is a deficient number, since it is larger than the sum of its proper divisors (1).

23313312332953 is an equidigital number, since it uses as much as digits as its factorization.

23313312332953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 787320, while the sum is 43.

The spelling of 23313312332953 in words is "twenty-three trillion, three hundred thirteen billion, three hundred twelve million, three hundred thirty-two thousand, nine hundred fifty-three".