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BaseRepresentation
bin1010111010110100110000…
…01010101101101101010101
310011000110200011010221000121
411131122120022231231111
511121400342023131013
6123022405533111541
75025524242363042
oct535323012555525
9104013604127017
1024011420130133
117718205761487
1228396a80285b1
131052362075b07
145d02321921c9
152b98d371d58d
hex15d6982adb55

24011420130133 has 2 divisors, whose sum is σ = 24011420130134. Its totient is φ = 24011420130132.

The previous prime is 24011420130127. The next prime is 24011420130143. The reversal of 24011420130133 is 33103102411042.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15806850463089 + 8204569667044 = 3975783^2 + 2864362^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-24011420130133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 24011420130098 and 24011420130107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24011420130143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12005710065066 + 12005710065067.

It is an arithmetic number, because the mean of its divisors is an integer number (12005710065067).

Almost surely, 224011420130133 is an apocalyptic number.

It is an amenable number.

24011420130133 is a deficient number, since it is larger than the sum of its proper divisors (1).

24011420130133 is an equidigital number, since it uses as much as digits as its factorization.

24011420130133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 24011420130133 its reverse (33103102411042), we get a palindrome (57114522541175).

The spelling of 24011420130133 in words is "twenty-four trillion, eleven billion, four hundred twenty million, one hundred thirty thousand, one hundred thirty-three".