Base | Representation |
---|---|
bin | 110110110110001110110110… |
… | …110000001010101110011001 |
3 | 1011122002112101010221002121122 |
4 | 312312032312300022232121 |
5 | 223104132222431403101 |
6 | 2213011313022215025 |
7 | 101544444020014634 |
oct | 6666166660125631 |
9 | 1148075333832548 |
10 | 241221314325401 |
11 | 6a951426345673 |
12 | 2307a382124475 |
13 | a47a0c2bcb4b7 |
14 | 437d2612bcc1b |
15 | 1cd4abecd251b |
hex | db63b6c0ab99 |
241221314325401 has 2 divisors, whose sum is σ = 241221314325402. Its totient is φ = 241221314325400.
The previous prime is 241221314325361. The next prime is 241221314325413. The reversal of 241221314325401 is 104523413122142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124770798907225 + 116450515418176 = 11170085^2 + 10791224^2 .
It is a cyclic number.
It is not a de Polignac number, because 241221314325401 - 234 = 241204134456217 is a prime.
It is not a weakly prime, because it can be changed into another prime (241221314325451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120610657162700 + 120610657162701.
It is an arithmetic number, because the mean of its divisors is an integer number (120610657162701).
Almost surely, 2241221314325401 is an apocalyptic number.
It is an amenable number.
241221314325401 is a deficient number, since it is larger than the sum of its proper divisors (1).
241221314325401 is an equidigital number, since it uses as much as digits as its factorization.
241221314325401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 241221314325401 its reverse (104523413122142), we get a palindrome (345744727447543).
The spelling of 241221314325401 in words is "two hundred forty-one trillion, two hundred twenty-one billion, three hundred fourteen million, three hundred twenty-five thousand, four hundred one".
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