Base | Representation |
---|---|
bin | 110110110111100011100110… |
… | …001111010101111011110001 |
3 | 1011122102020020110120120101202 |
4 | 312313203212033111323301 |
5 | 223112130100131341040 |
6 | 2213121202003340545 |
7 | 101554144611620204 |
oct | 6667434617257361 |
9 | 1148366213516352 |
10 | 241312305340145 |
11 | 6a986a79402806 |
12 | 23093b36981755 |
13 | a485864132c20 |
14 | 4383813a6993b |
15 | 1cd7148168015 |
hex | db78e63d5ef1 |
241312305340145 has 32 divisors (see below), whose sum is σ = 329064707865600. Its totient is φ = 168536844900864.
The previous prime is 241312305340123. The next prime is 241312305340153. The reversal of 241312305340145 is 541043503213142.
It is a cyclic number.
It is not a de Polignac number, because 241312305340145 - 236 = 241243585863409 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 241312305340099 and 241312305340108.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 906681065 + ... + 906947174.
It is an arithmetic number, because the mean of its divisors is an integer number (10283272120800).
Almost surely, 2241312305340145 is an apocalyptic number.
It is an amenable number.
241312305340145 is a deficient number, since it is larger than the sum of its proper divisors (87752402525455).
241312305340145 is a wasteful number, since it uses less digits than its factorization.
241312305340145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1813628369.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 241312305340145 its reverse (541043503213142), we get a palindrome (782355808553287).
The spelling of 241312305340145 in words is "two hundred forty-one trillion, three hundred twelve billion, three hundred five million, three hundred forty thousand, one hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •