Base | Representation |
---|---|
bin | 1110001101011010110… |
… | …0011010011101101011 |
3 | 212100010011002210102011 |
4 | 3203112230122131223 |
5 | 12444424223314111 |
6 | 304051445420351 |
7 | 23431344625516 |
oct | 3432654323553 |
9 | 770104083364 |
10 | 244120135531 |
11 | 945924a8028 |
12 | 3b38b40a6b7 |
13 | 1a035b6694c |
14 | bb5b955d7d |
15 | 653ba12021 |
hex | 38d6b1a76b |
244120135531 has 2 divisors, whose sum is σ = 244120135532. Its totient is φ = 244120135530.
The previous prime is 244120135487. The next prime is 244120135543. The reversal of 244120135531 is 135531021442.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 244120135531 - 211 = 244120133483 is a prime.
It is a super-2 number, since 2×2441201355312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 244120135493 and 244120135502.
It is not a weakly prime, because it can be changed into another prime (244120535531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 122060067765 + 122060067766.
It is an arithmetic number, because the mean of its divisors is an integer number (122060067766).
Almost surely, 2244120135531 is an apocalyptic number.
244120135531 is a deficient number, since it is larger than the sum of its proper divisors (1).
244120135531 is an equidigital number, since it uses as much as digits as its factorization.
244120135531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 244120135531 its reverse (135531021442), we get a palindrome (379651156973).
The spelling of 244120135531 in words is "two hundred forty-four billion, one hundred twenty million, one hundred thirty-five thousand, five hundred thirty-one".
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