Base | Representation |
---|---|
bin | 110111101101110100100010… |
… | …000010111001000100111111 |
3 | 1012010121201112022210011002020 |
4 | 313231310202002321010333 |
5 | 224104224131110301421 |
6 | 2225054234312531223 |
7 | 102420436563154104 |
oct | 6755644202710477 |
9 | 1163551468704066 |
10 | 245041340322111 |
11 | 710944a3440843 |
12 | 235967a10b0b13 |
13 | a6963b7585458 |
14 | 44720c806caab |
15 | 1d4e14a9bbdc6 |
hex | dedd220b913f |
245041340322111 has 4 divisors (see below), whose sum is σ = 326721787096152. Its totient is φ = 163360893548072.
The previous prime is 245041340322071. The next prime is 245041340322131. The reversal of 245041340322111 is 111223043140542.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 245041340322111 - 27 = 245041340321983 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (245041340322131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40840223387016 + ... + 40840223387021.
It is an arithmetic number, because the mean of its divisors is an integer number (81680446774038).
Almost surely, 2245041340322111 is an apocalyptic number.
245041340322111 is a deficient number, since it is larger than the sum of its proper divisors (81680446774041).
245041340322111 is an equidigital number, since it uses as much as digits as its factorization.
245041340322111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81680446774040.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 245041340322111 its reverse (111223043140542), we get a palindrome (356264383462653).
The spelling of 245041340322111 in words is "two hundred forty-five trillion, forty-one billion, three hundred forty million, three hundred twenty-two thousand, one hundred eleven".
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