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25400121 = 38466707
BaseRepresentation
bin110000011100…
…1001100111001
31202210110102020
41200321030321
523000300441
62304225053
7425616555
oct140711471
952713366
1025400121
111337953a
12860b189
135354376
143532865
15236ae66
hex1839339

25400121 has 4 divisors (see below), whose sum is σ = 33866832. Its totient is φ = 16933412.

The previous prime is 25400083. The next prime is 25400147. The reversal of 25400121 is 12100452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25400121 - 218 = 25137977 is a prime.

It is a super-2 number, since 2×254001212 = 1290332293629282, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 25400121.

It is not an unprimeable number, because it can be changed into a prime (25400171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4233351 + ... + 4233356.

It is an arithmetic number, because the mean of its divisors is an integer number (8466708).

Almost surely, 225400121 is an apocalyptic number.

It is an amenable number.

25400121 is a deficient number, since it is larger than the sum of its proper divisors (8466711).

25400121 is an equidigital number, since it uses as much as digits as its factorization.

25400121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8466710.

The product of its (nonzero) digits is 80, while the sum is 15.

The square root of 25400121 is about 5039.8532716737. The cubic root of 25400121 is about 293.9534726686.

Adding to 25400121 its reverse (12100452), we get a palindrome (37500573).

The spelling of 25400121 in words is "twenty-five million, four hundred thousand, one hundred twenty-one".

Divisors: 1 3 8466707 25400121