Base | Representation |
---|---|
bin | 100101001010011000111… |
… | …010101111111100101001 |
3 | 100001010202001022001212021 |
4 | 211022120322233330221 |
5 | 313320113141031101 |
6 | 5233104420544441 |
7 | 352334644533334 |
oct | 45123072577451 |
9 | 10033661261767 |
10 | 2553776111401 |
11 | 8a5061046759 |
12 | 352b32552121 |
13 | 156a87873bb8 |
14 | 8b863b1761b |
15 | 46669c535a1 |
hex | 25298eaff29 |
2553776111401 has 4 divisors (see below), whose sum is σ = 2553847380304. Its totient is φ = 2553704842500.
The previous prime is 2553776111353. The next prime is 2553776111431. The reversal of 2553776111401 is 1041116773552.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2553776111401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2553776111431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35580675 + ... + 35652376.
It is an arithmetic number, because the mean of its divisors is an integer number (638461845076).
Almost surely, 22553776111401 is an apocalyptic number.
It is an amenable number.
2553776111401 is a deficient number, since it is larger than the sum of its proper divisors (71268903).
2553776111401 is an equidigital number, since it uses as much as digits as its factorization.
2553776111401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71268902.
The product of its (nonzero) digits is 176400, while the sum is 43.
The spelling of 2553776111401 in words is "two trillion, five hundred fifty-three billion, seven hundred seventy-six million, one hundred eleven thousand, four hundred one".
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