Base | Representation |
---|---|

bin | 11000100111011011… |

… | …010000110101100011 |

3 | 2112020001002020020112 |

4 | 120213123100311203 |

5 | 413112400341201 |

6 | 20050425401535 |

7 | 1623664010015 |

oct | 304733206543 |

9 | 75201066215 |

10 | 26431262051 |

11 | 10233838427 |

12 | 51579392ab |

13 | 2652c0c53c |

14 | 13ca4b61b5 |

15 | a4a6900bb |

hex | 6276d0d63 |

26431262051 has 2 divisors, whose sum is σ = 26431262052. Its totient is φ = 26431262050.

The previous prime is 26431262027. The next prime is 26431262101. The reversal of 26431262051 is 15026213462.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^{k}-26431262051 is a prime.

It is a super-2 number, since 2×26431262051^{2} (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 26431261999 and 26431262017.

It is not a weakly prime, because it can be changed into another prime (26431262651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13215631025 + 13215631026.

It is an arithmetic number, because the mean of its divisors is an integer number (13215631026).

Almost surely, 2^{26431262051} is an apocalyptic number.

26431262051 is a deficient number, since it is larger than the sum of its proper divisors (1).

26431262051 is an equidigital number, since it uses as much as digits as its factorization.

26431262051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

The spelling of 26431262051 in words is "twenty-six billion, four hundred thirty-one million, two hundred sixty-two thousand, fifty-one".

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