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265314331 is a prime number
BaseRepresentation
bin11111101000001…
…10000000011011
3200111020100211201
433310012000123
51020410024311
642154335031
76401064112
oct1764060033
9614210751
10265314331
11126843647
1274a2a477
1342c75139
1427344c79
151845b9c1
hexfd0601b

265314331 has 2 divisors, whose sum is σ = 265314332. Its totient is φ = 265314330.

The previous prime is 265314307. The next prime is 265314341. The reversal of 265314331 is 133413562.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 265314331 - 211 = 265312283 is a prime.

It is a super-2 number, since 2×2653143312 = 140783388467955122, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 265314331.

It is not a weakly prime, because it can be changed into another prime (265314341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132657165 + 132657166.

It is an arithmetic number, because the mean of its divisors is an integer number (132657166).

Almost surely, 2265314331 is an apocalyptic number.

265314331 is a deficient number, since it is larger than the sum of its proper divisors (1).

265314331 is an equidigital number, since it uses as much as digits as its factorization.

265314331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 28.

The square root of 265314331 is about 16288.4723347526. The cubic root of 265314331 is about 642.5696904930.

Adding to 265314331 its reverse (133413562), we get a palindrome (398727893).

The spelling of 265314331 in words is "two hundred sixty-five million, three hundred fourteen thousand, three hundred thirty-one".