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26873163207413 is a prime number
BaseRepresentation
bin1100001110000111001010…
…10110001101001011110101
310112011001022221121211020022
412013003211112031023311
512010242214240114123
6133053205531014525
75442344015235605
oct607034526151365
9115131287554208
1026873163207413
118620932059856
123020247b9a445
1311cc1891936b3
1468c94d156c05
153190752a31c8
hex1870e558d2f5

26873163207413 has 2 divisors, whose sum is σ = 26873163207414. Its totient is φ = 26873163207412.

The previous prime is 26873163207299. The next prime is 26873163207421. The reversal of 26873163207413 is 31470236137862.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26803161689329 + 70001518084 = 5177177^2 + 264578^2 .

It is a cyclic number.

It is not a de Polignac number, because 26873163207413 - 210 = 26873163206389 is a prime.

It is a super-3 number, since 3×268731632074133 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (26873163200413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13436581603706 + 13436581603707.

It is an arithmetic number, because the mean of its divisors is an integer number (13436581603707).

Almost surely, 226873163207413 is an apocalyptic number.

It is an amenable number.

26873163207413 is a deficient number, since it is larger than the sum of its proper divisors (1).

26873163207413 is an equidigital number, since it uses as much as digits as its factorization.

26873163207413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6096384, while the sum is 53.

The spelling of 26873163207413 in words is "twenty-six trillion, eight hundred seventy-three billion, one hundred sixty-three million, two hundred seven thousand, four hundred thirteen".