3000133131113 has 4 divisors (see below), whose sum is σ = 3000136595328. Its totient is φ = 3000129666900.

The previous prime is 3000133131019. The next prime is 3000133131179. The reversal of 3000133131113 is 3111313310003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 3000133131113 - 2¹⁴ = 3000133114729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3000133131913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 854288 + ... + 2594238.

It is an arithmetic number, because the mean of its divisors is an integer number (750034148832).

Almost surely, 2^{3000133131113} is an apocalyptic number.

It is an amenable number.

3000133131113 is a deficient number, since it is larger than the sum of its proper divisors (3464215).

3000133131113 is a wasteful number, since it uses less digits than its factorization.

3000133131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3464214.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 3000133131113 its reverse (3111313310003), we get a palindrome (6111446441116).

The spelling of 3000133131113 in words is "three trillion, one hundred thirty-three million, one hundred thirty-one thousand, one hundred thirteen".