Base | Representation |
---|---|
bin | 11100000010101101… |
… | …110101101110010011 |
3 | 2212201102220212012011 |
4 | 130002231311232103 |
5 | 443131221421120 |
6 | 21455453043351 |
7 | 2114106453514 |
oct | 340255655623 |
9 | 85642825164 |
10 | 30110342035 |
11 | 118515596a4 |
12 | 5a03a86557 |
13 | 2abb1ba047 |
14 | 1658d6ca0b |
15 | bb3672c5a |
hex | 702b75b93 |
30110342035 has 4 divisors (see below), whose sum is σ = 36132410448. Its totient is φ = 24088273624.
The previous prime is 30110341993. The next prime is 30110342051. The reversal of 30110342035 is 53024301103.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53024301103 = 37 ⋅1433089219.
It is a cyclic number.
It is not a de Polignac number, because 30110342035 - 231 = 27962858387 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 30110341997 and 30110342015.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3011034199 + ... + 3011034208.
It is an arithmetic number, because the mean of its divisors is an integer number (9033102612).
Almost surely, 230110342035 is an apocalyptic number.
30110342035 is a deficient number, since it is larger than the sum of its proper divisors (6022068413).
30110342035 is an equidigital number, since it uses as much as digits as its factorization.
30110342035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6022068412.
The product of its (nonzero) digits is 1080, while the sum is 22.
Adding to 30110342035 its reverse (53024301103), we get a palindrome (83134643138).
The spelling of 30110342035 in words is "thirty billion, one hundred ten million, three hundred forty-two thousand, thirty-five".
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