Base | Representation |
---|---|
bin | 101100011011110001010… |
… | …101011010101000110001 |
3 | 101210220112222020110201111 |
4 | 230123301111122220301 |
5 | 400012004240001340 |
6 | 10254425233233321 |
7 | 433414655143534 |
oct | 54336125325061 |
9 | 11726488213644 |
10 | 3053475703345 |
11 | a77a76481131 |
12 | 41394aa02841 |
13 | 191c316b0212 |
14 | a7b0909ca1b |
15 | 546642e6aea |
hex | 2c6f155aa31 |
3053475703345 has 4 divisors (see below), whose sum is σ = 3664170844020. Its totient is φ = 2442780562672.
The previous prime is 3053475703339. The next prime is 3053475703387. The reversal of 3053475703345 is 5433075743503.
3053475703345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1629727985664 + 1423747717681 = 1276608^2 + 1193209^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3053475703345 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305347570330 + ... + 305347570339.
It is an arithmetic number, because the mean of its divisors is an integer number (916042711005).
Almost surely, 23053475703345 is an apocalyptic number.
It is an amenable number.
3053475703345 is a deficient number, since it is larger than the sum of its proper divisors (610695140675).
3053475703345 is an equidigital number, since it uses as much as digits as its factorization.
3053475703345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 610695140674.
The product of its (nonzero) digits is 7938000, while the sum is 49.
The spelling of 3053475703345 in words is "three trillion, fifty-three billion, four hundred seventy-five million, seven hundred three thousand, three hundred forty-five".
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