Base | Representation |
---|---|
bin | 11100111101101101… |
… | …100101101010101101 |
3 | 2222021102101101210020 |
4 | 130331231211222231 |
5 | 1002143113211023 |
6 | 22142011432353 |
7 | 2150455521546 |
oct | 347555455255 |
9 | 88242341706 |
10 | 31100132013 |
11 | 1220a239545 |
12 | 603b4556b9 |
13 | 2c18290ba2 |
14 | 17105bd4cd |
15 | c204d8de3 |
hex | 73db65aad |
31100132013 has 8 divisors (see below), whose sum is σ = 41467827648. Its totient is φ = 20732928864.
The previous prime is 31100131963. The next prime is 31100132029. The reversal of 31100132013 is 31023100113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31100132013 - 29 = 31100131501 is a prime.
It is a super-2 number, since 2×311001320132 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31100131983 and 31100132001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31100132813) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65520 + ... + 257862.
It is an arithmetic number, because the mean of its divisors is an integer number (5183478456).
Almost surely, 231100132013 is an apocalyptic number.
It is an amenable number.
31100132013 is a deficient number, since it is larger than the sum of its proper divisors (10367695635).
31100132013 is a wasteful number, since it uses less digits than its factorization.
31100132013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246243.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 31100132013 its reverse (31023100113), we get a palindrome (62123232126).
The spelling of 31100132013 in words is "thirty-one billion, one hundred million, one hundred thirty-two thousand, thirteen".
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