Base | Representation |
---|---|

bin | 11100111110011011… |

… | …010010001110100011 |

3 | 2222022020220222212211 |

4 | 130332123102032203 |

5 | 1002204200023021 |

6 | 22143120302551 |

7 | 2150662403002 |

oct | 347633221643 |

9 | 88266828784 |

10 | 31112111011 |

11 | 12215a80543 |

12 | 6043471a57 |

13 | 2c1a8c6457 |

14 | 171201ac39 |

15 | c215a33e1 |

hex | 73e6d23a3 |

31112111011 has 2 divisors, whose sum is σ = 31112111012. Its totient is φ = 31112111010.

The previous prime is 31112110987. The next prime is 31112111029. The reversal of 31112111011 is 11011121113.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^{k}-31112111011 is a prime.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 31112110982 and 31112111000.

It is not a weakly prime, because it can be changed into another prime (31112112011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556055505 + 15556055506.

It is an arithmetic number, because the mean of its divisors is an integer number (15556055506).

Almost surely, 2^{31112111011} is an apocalyptic number.

31112111011 is a deficient number, since it is larger than the sum of its proper divisors (1).

31112111011 is an equidigital number, since it uses as much as digits as its factorization.

31112111011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 31112111011 its reverse (11011121113), we get a palindrome (42123232124).

The spelling of 31112111011 in words is "thirty-one billion, one hundred twelve million, one hundred eleven thousand, eleven".

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