Base | Representation |
---|---|
bin | 1011111001110000000101 |
3 | 12212112000111 |
4 | 23321300011 |
5 | 1244321013 |
6 | 150513021 |
7 | 35343412 |
oct | 13716005 |
9 | 5775014 |
10 | 3120133 |
11 | 1841225 |
12 | 1065771 |
13 | 853243 |
14 | 5b3109 |
15 | 41973d |
hex | 2f9c05 |
3120133 has 4 divisors (see below), whose sum is σ = 3142720. Its totient is φ = 3097548.
The previous prime is 3120127. The next prime is 3120137. The reversal of 3120133 is 3310213.
3120133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3310213 = 1549 ⋅2137.
It is a cyclic number.
It is not a de Polignac number, because 3120133 - 221 = 1022981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3120137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11085 + ... + 11362.
It is an arithmetic number, because the mean of its divisors is an integer number (785680).
Almost surely, 23120133 is an apocalyptic number.
It is an amenable number.
3120133 is a deficient number, since it is larger than the sum of its proper divisors (22587).
3120133 is a wasteful number, since it uses less digits than its factorization.
3120133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22586.
The product of its (nonzero) digits is 54, while the sum is 13.
The square root of 3120133 is about 1766.3898210757. The cubic root of 3120133 is about 146.1249477703.
Adding to 3120133 its reverse (3310213), we get a palindrome (6430346).
It can be divided in two parts, 31 and 20133, that added together give a square (20164 = 1422).
The spelling of 3120133 in words is "three million, one hundred twenty thousand, one hundred thirty-three".
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