Base | Representation |
---|---|
bin | 100011100101110110001010… |
… | …0010000111011000111010011 |
3 | 1112001110200222021020210022111 |
4 | 1013023230110100323013103 |
5 | 312013223203043402431 |
6 | 3025455552330250151 |
7 | 122641120422122302 |
oct | 10713542420730723 |
9 | 1461420867223274 |
10 | 313064801153491 |
11 | 90830044739a22 |
12 | 2b142080586957 |
13 | 1058bb65406a2a |
14 | 57445bac10439 |
15 | 262d801ec27b1 |
hex | 11cbb1443b1d3 |
313064801153491 has 2 divisors, whose sum is σ = 313064801153492. Its totient is φ = 313064801153490.
The previous prime is 313064801153381. The next prime is 313064801153521. The reversal of 313064801153491 is 194351108460313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313064801153491 - 245 = 277880429064659 is a prime.
It is not a weakly prime, because it can be changed into another prime (313064801153791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156532400576745 + 156532400576746.
It is an arithmetic number, because the mean of its divisors is an integer number (156532400576746).
Almost surely, 2313064801153491 is an apocalyptic number.
313064801153491 is a deficient number, since it is larger than the sum of its proper divisors (1).
313064801153491 is an equidigital number, since it uses as much as digits as its factorization.
313064801153491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 49.
The spelling of 313064801153491 in words is "three hundred thirteen trillion, sixty-four billion, eight hundred one million, one hundred fifty-three thousand, four hundred ninety-one".
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