Base | Representation |
---|---|
bin | 1001001110011101010… |
… | …01010111111100101111 |
3 | 1010022020020121102002110 |
4 | 10213032221113330233 |
5 | 20143203342040403 |
6 | 401343320455103 |
7 | 31621354562544 |
oct | 4471651277457 |
9 | 1108206542073 |
10 | 316999565103 |
11 | 112490a99161 |
12 | 5152a61a493 |
13 | 23b7b9cc080 |
14 | 114b2b4abcb |
15 | 83a4cec103 |
hex | 49cea57f2f |
316999565103 has 16 divisors (see below), whose sum is σ = 479135646080. Its totient is φ = 184809462624.
The previous prime is 316999565093. The next prime is 316999565189. The reversal of 316999565103 is 301565999613.
It is not a de Polignac number, because 316999565103 - 26 = 316999565039 is a prime.
It is a super-2 number, since 2×3169995651032 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (57).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (316999565503) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 213899101 + ... + 213900582.
It is an arithmetic number, because the mean of its divisors is an integer number (29945977880).
Almost surely, 2316999565103 is an apocalyptic number.
316999565103 is a deficient number, since it is larger than the sum of its proper divisors (162136080977).
316999565103 is a wasteful number, since it uses less digits than its factorization.
316999565103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 427799718.
The product of its (nonzero) digits is 5904900, while the sum is 57.
The spelling of 316999565103 in words is "three hundred sixteen billion, nine hundred ninety-nine million, five hundred sixty-five thousand, one hundred three".
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