3214111 has 4 divisors (see below), whose sum is σ = 3317824. Its totient is φ = 3110400.

The previous prime is 3214109. The next prime is 3214129. The reversal of 3214111 is 1114123.

3214111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1114123 = 859 ⋅1297.

It is a 9-Lehmer number, since φ(3214111) divides (3214111-1)⁹.

It is a cyclic number.

It is not a de Polignac number, because 3214111 - 2¹ = 3214109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3214091 and 3214100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3214171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51810 + ... + 51871.

It is an arithmetic number, because the mean of its divisors is an integer number (829456).

Almost surely, 2^3214111 is an apocalyptic number.

3214111 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

3214111 is a deficient number, since it is larger than the sum of its proper divisors (103713).

3214111 is a wasteful number, since it uses less digits than its factorization.

3214111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103712.

The product of its digits is 24, while the sum is 13.

The square root of 3214111 is about 1792.7941878531. The cubic root of 3214111 is about 147.5775480375.

Adding to 3214111 its reverse (1114123), we get a palindrome (4328234).

The spelling of 3214111 in words is "three million, two hundred fourteen thousand, one hundred eleven".