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323011131214234 = 2161505565607117
BaseRepresentation
bin100100101110001101110001…
…1101111000000100110011010
31120100200120012010000122021211
41021130123203233000212122
5314314203244042323414
63102553133134253334
7125015532643520521
oct11134334357004632
91510616163018254
10323011131214234
1193a15284762241
123028987a35724a
1310b30a85395438
1459a9b720554b8
1527523da2963c4
hex125c6e3bc099a

323011131214234 has 4 divisors (see below), whose sum is σ = 484516696821354. Its totient is φ = 161505565607116.

The previous prime is 323011131214207. The next prime is 323011131214237. The reversal of 323011131214234 is 432412131110323.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 213307397872209 + 109703733342025 = 14605047^2 + 10473955^2 .

It is a junction number, because it is equal to n+sod(n) for n = 323011131214196 and 323011131214205.

It is not an unprimeable number, because it can be changed into a prime (323011131214237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80752782803557 + ... + 80752782803560.

Almost surely, 2323011131214234 is an apocalyptic number.

323011131214234 is a deficient number, since it is larger than the sum of its proper divisors (161505565607120).

323011131214234 is a wasteful number, since it uses less digits than its factorization.

323011131214234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161505565607119.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 323011131214234 its reverse (432412131110323), we get a palindrome (755423262324557).

The spelling of 323011131214234 in words is "three hundred twenty-three trillion, eleven billion, one hundred thirty-one million, two hundred fourteen thousand, two hundred thirty-four".

Divisors: 1 2 161505565607117 323011131214234