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323212000000051 is a prime number
BaseRepresentation
bin100100101111101011010100…
…0011100100111100000110011
31120101101202200000002012212201
41021133112220130213200303
5314331001134000000201
63103225313141404031
7125036203444160011
oct11137265034474063
91511352600065781
10323212000000051
1193a92491976048
1230300798a09617
1310b469b769c456
1459b57896898b1
152757744b2d801
hex125f5a8727833

323212000000051 has 2 divisors, whose sum is σ = 323212000000052. Its totient is φ = 323212000000050.

The previous prime is 323211999999949. The next prime is 323212000000069. The reversal of 323212000000051 is 150000000212323.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 323212000000051 - 211 = 323211999998003 is a prime.

It is a super-3 number, since 3×3232120000000513 (a number of 45 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 323211999999965 and 323212000000028.

It is not a weakly prime, because it can be changed into another prime (323212000000081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161606000000025 + 161606000000026.

It is an arithmetic number, because the mean of its divisors is an integer number (161606000000026).

Almost surely, 2323212000000051 is an apocalyptic number.

323212000000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

323212000000051 is an equidigital number, since it uses as much as digits as its factorization.

323212000000051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 19.

Adding to 323212000000051 its reverse (150000000212323), we get a palindrome (473212000212374).

The spelling of 323212000000051 in words is "three hundred twenty-three trillion, two hundred twelve billion, fifty-one", and thus it is an aban number.