323503540460413 has 4 divisors (see below), whose sum is σ = 323760493234080. Its totient is φ = 323246587686748.

The previous prime is 323503540460407. The next prime is 323503540460447. The reversal of 323503540460413 is 314064045305323.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 323503540460413 - 2⁴⁵ = 288319168371581 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 323503540460413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (323503540460713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128476384945 + ... + 128476387462.

It is an arithmetic number, because the mean of its divisors is an integer number (80940123308520).

Almost surely, 2^{323503540460413} is an apocalyptic number.

It is an amenable number.

323503540460413 is a deficient number, since it is larger than the sum of its proper divisors (256952773667).

323503540460413 is a wasteful number, since it uses less digits than its factorization.

323503540460413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 256952773666.

The product of its (nonzero) digits is 1555200, while the sum is 43.

Adding to 323503540460413 its reverse (314064045305323), we get a palindrome (637567585765736).

The spelling of 323503540460413 in words is "three hundred twenty-three trillion, five hundred three billion, five hundred forty million, four hundred sixty thousand, four hundred thirteen".