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324332012323 = 1129484728393
BaseRepresentation
bin1001011100000111011…
…00011100001100100011
31011000011020220022201201
410232003230130030203
520303212443343243
6404555052342031
732301151421644
oct4560354341443
91130136808651
10324332012323
11115603a692a0
1252a36174917
1324779b53937
14119aa8c56cb
1586838d404d
hex4b83b1c323

324332012323 has 4 divisors (see below), whose sum is σ = 353816740728. Its totient is φ = 294847283920.

The previous prime is 324332012317. The next prime is 324332012327. The reversal of 324332012323 is 323210233423.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-324332012323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 324332012291 and 324332012300.

It is not an unprimeable number, because it can be changed into a prime (324332012327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14742364186 + ... + 14742364207.

It is an arithmetic number, because the mean of its divisors is an integer number (88454185182).

Almost surely, 2324332012323 is an apocalyptic number.

324332012323 is a deficient number, since it is larger than the sum of its proper divisors (29484728405).

324332012323 is a wasteful number, since it uses less digits than its factorization.

324332012323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29484728404.

The product of its (nonzero) digits is 15552, while the sum is 28.

Adding to 324332012323 its reverse (323210233423), we get a palindrome (647542245746).

The spelling of 324332012323 in words is "three hundred twenty-four billion, three hundred thirty-two million, twelve thousand, three hundred twenty-three".

Divisors: 1 11 29484728393 324332012323